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is formed about A and C。 Nor if A does not belong to some B�察�but



belongs to all C�察�will a syllogism be possible about B and C。 A



similar proof can be given if the premisses are not universal。 For



either both premisses arrived at by the conversion must be particular��



or the universal premiss must refer to the minor extreme。 But we found



that no syllogism is possible thus either in the first or in the



middle figure。 But if the conclusion is converted into its



contradictory�察�both the premisses can be refuted。 For if A belongs



to no B�察�and B to all C�察�then A belongs to no C�此�again if A belongs to



no B�察�and to all C�察�B belongs to no C。 And similarly if one of the



premisses is not universal。 For if A belongs to no B�察�and B to some C��



A will not belong to some C�此�if A belongs to no B�察�and to C�察�B will



belong to no C。



  Similarly if the original syllogism is negative。 Suppose it has been



proved that A does not belong to some B�察�BC being affirmative�察�AC



being negative�此�for it was thus that�察�as we saw�察�a syllogism could



be made。 Whenever then the contrary of the conclusion is assumed a



syllogism will not be possible。 For if A belongs to some B�察�and B to



all C�察�no syllogism is possible ��as we saw�� about A and C。 Nor�察�if A



belongs to some B�察�and to no C�察�was a syllogism possible concerning



B and C。 Therefore the premisses are not refuted。 But when the



contradictory of the conclusion is assumed�察�they are refuted。 For if A



belongs to all B�察�and B to C�察�A belongs to all C�此�but A was supposed



originally to belong to no C。 Again if A belongs to all B�察�and to no



C�察�then B belongs to no C�此�but it was supposed to belong to all C。 A



similar proof is possible if the premisses are not universal。 For AC



becomes universal and negative�察�the other premiss particular and



affirmative。 If then A belongs to all B�察�and B to some C�察�it results



that A belongs to some C�此�but it was supposed to belong to no C。 Again



if A belongs to all B�察�and to no C�察�then B belongs to no C�此�but it was



assumed to belong to some C。 If A belongs to some B and B to some C��



no syllogism results�此�nor yet if A belongs to some B�察�and to no C。



Thus in one way the premisses are refuted�察�in the other way they are



not。



  From what has been said it is clear how a syllogism results in



each figure when the conclusion is converted�察�when a result contrary



to the premiss�察�and when a result contradictory to the premiss�察�is



obtained。 It is clear that in the first figure the syllogisms are



formed through the middle and the last figures�察�and the premiss



which concerns the minor extreme is alway refuted through the middle



figure�察�the premiss which concerns the major through the last



figure。 In the second figure syllogisms proceed through the first



and the last figures�察�and the premiss which concerns the minor extreme



is always refuted through the first figure�察�the premiss which concerns



the major extreme through the last。 In the third figure the refutation



proceeds through the first and the middle figures�察�the premiss which



concerns the major is always refuted through the first figure�察�the



premiss which concerns the minor through the middle figure。



                                11







  It is clear then what conversion is�察�how it is effected in each



figure�察�and what syllogism results。 The syllogism per impossibile is



proved when the contradictory of the conclusion stated and another



premiss is assumed�察�it can be made in all the figures。 For it



resembles conversion�察�differing only in this�此�conversion takes place



after a syllogism has been formed and both the premisses have been



taken�察�but a reduction to the impossible takes place not because the



contradictory has been agreed to already�察�but because it is clear that



it is true。 The terms are alike in both�察�and the premisses of both are



taken in the same way。 For example if A belongs to all B�察�C being



middle�察�then if it is supposed that A does not belong to all B or



belongs to no B�察�but to all C ��which was admitted to be true���察�it



follows that C belongs to no B or not to all B。 But this is



impossible�此�consequently the supposition is false�此�its contradictory



then is true。 Similarly in the other figures�此�for whatever moods admit



of conversion admit also of the reduction per impossibile。



  All the problems can be proved per impossibile in all the figures��



excepting the universal affirmative�察�which is proved in the middle and



third figures�察�but not in the first。 Suppose that A belongs not to all



B�察�or to no B�察�and take besides another premiss concerning either of



the terms�察�viz。 that C belongs to all A�察�or that B belongs to all D��



thus we get the first figure。 If then it is supposed that A does not



belong to all B�察�no syllogism results whichever term the assumed



premiss concerns�察�but if it is supposed that A belongs to no B�察�when



the premiss BD is assumed as well we shall prove syllogistically



what is false�察�but not the problem proposed。 For if A belongs to no B��



and B belongs to all D�察�A belongs to no D。 Let this be impossible��



it is false then A belongs to no B。 But the universal affirmative is



not necessarily true if the universal negative is false。 But if the



premiss CA is assumed as well�察�no syllogism results�察�nor does it do so



when it is supposed that A does not belong to all B。 Consequently it



is clear that the universal affirmative cannot be proved in the



first figure per impossibile。



  But the particular affirmative and the universal and particular



negatives can all be proved。 Suppose that A belongs to no B�察�and let



it have been assumed that B belongs to all or to some C。 Then it is



necessary that A should belong to no C or not to all C。 But this is



impossible ��for let it be true and clear that A belongs to all C����



consequently if this is false�察�it is necessary that A should belong to



some B。 But if the other premiss assumed relates to A�察�no syllogism



will be possible。 Nor can a conclusion be drawn when the contrary of



the conclusion is supposed�察�e。g。 that A does not belong to some B。



Clearly then we must suppose the contradictory。



  Again suppose that A belongs to some B�察�and let it have been assumed



that C belongs to all A。 It is necessary then that C should belong



to some B。 But let this be impossible�察�so that the supposition is



false�此�in that case it is true that A belongs to no B。 We may



proceed in the same way if the proposition CA has been taken as



negative。 But if the premiss assumed concerns B�察�no syllogism will



be possible。 If the contrary is supposed�察�we shall have a syllogism



and an impossible conclusion�察�but the problem in hand is not proved。



Suppose that A belongs to all B�察�and let it have been assumed that C



belongs to all A。 It is necessary then that C should belong to all



B。 But this is impossible�察�so that it is false that A belongs to all



B。 But we have not yet shown it to be necessary that A belongs to no



B�察�if it does not belong to all B。 Similarly if the other premiss



taken concerns B�察�we shall have a syllogism and a conclusion which



is impossible�察�but the hypothesis is not refuted。 Therefore it is



the contradictory that we must suppose。



  To prove that A does not belong to all B�察�we must suppose that it



belongs to all B�此�for if A belongs to all B�察�and C to all A�察�then C



belongs to all B�察�so that if this is impossible�察�the hypothesis is



false。 Similarly if the other premiss assumed concerns B。 The same



results if the original proposition CA was negative�此�for thus also



we get a syllogism。 But if the negative proposition concerns B��



nothing is proved。 If the hypothesis is that A belongs not to all



but to some B�察�it is not proved that A belongs not to all B�察�but



that it belongs to no B。 For if A belongs to some B�察�and C to all A��



then C will belong to some B。 If then this is impossible�察�it is



false that A belongs to some B�察�consequently it is true that A belongs



to no B。 But if this is proved�察�the truth is refuted as well�察�for



the original conclusion was that A belongs to some B�察�and does not



belong to some B。 Further the impossible does not result from the



hypothesis�此�for then the hypothesis would be false�察�since it is



impossible to draw a false conclusion from true premisses�此�but in fact



it is true�此�for A belongs to some B。 Consequently we must not



suppose that A belongs to some B�察�but that it belongs to all B。



Similarly if we should be proving that A does not belong to some B��



for if 'not to belong to some' and 'to belong not to all' have the



same meaning�察�the demonstration of both will be identical。



  It is clear then that not the contrary but the contradictory ought



to be supposed in all the syllogisms。 For thus we shall have necessity



of inference�察�and the claim we make is one that will be generally



accepted。 For if of everything one or other of two contradictory



statements holds good�察�then if it is proved that the negation does not



hold�察�the affirmation must be true。 Again if it is not admitted that



the affirmation is true�察�the claim that the negation is true will be



generally accepted。 But in neither way does it suit to maintain the



contrary�此�for it is not necessary that if the universal negative is



false�察�the universal affirmative should be true�察�nor is it generally



accepted that if the one is false the other is true。







                                12







  It is clear then that in the first figure all problems except the



universal affirmative are proved per impossibile。 But in the middle



and the last figures this also is proved。 Suppose that A does not



belong to all B�察�and let it have been assumed that A belongs to all C。



If then A belongs not to all B�察�but to all C�察�C will not belong to all



B。 But this is impossible ��for suppose it to be clear that C belongs



to all B���此�consequently the hypothesis is false。 It is true then



that A belongs to all B。 But if the contrary is supposed�察�we shall



have a syllogism and a result which is impossible�此�but the problem



in hand is not proved。 For if A belongs to no B�察�and to all C�察�C



will belong to no B。 This is impossible�察�so that it is false that A



belongs to no B。 But though this is false�察�it does not follow that



it is true that A belongs to all B。



  When A belongs to some B�察�suppose that A belongs to no B�察�and let



A belong to all C。 It is necessary then that C should belong to no



B。 Consequently�察�if this is impos

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